정보 보관 ver1.0
jQuery.ajax()
James Wetzel
2012. 9. 19. 17:18
Example: Send an id as data to the server, save some data to the server, and notify the user once it's complete. If the request fails, alert the user.
var menuId = $("ul.nav").first().attr("id");
var request = $.ajax({
url: "script.php",
type: "POST",
data: {id : menuId},
dataType: "html"
});
request.done(function(msg) {
$("#log").html( msg );
});
request.fail(function(jqXHR, textStatus) {
alert( "Request failed: " + textStatus );
});
$.ajax({ url: "http://fiddle.jshell.net/favicon.png", beforeSend: function ( xhr ) { xhr.overrideMimeType("text/plain; charset=x-user-defined"); } }).done(function ( data ) { if( console && console.log ) { console.log("Sample of data:", data.slice(0, 100)); } });
상세 내용: http://api.jquery.com/jQuery.ajax/
728x90
반응형